Pregunta
factorise fully \( 6.3 a x+3 a y-x-y \)
Ask by Ruiz Adkins. in South Africa
Feb 03,2025
Solución de tutoría real
Respuesta verificada por el tutor
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The fully factored form is \(\frac{1}{10}(63ax + 30ay - 10x - 10y)\).
Solución
Factor the expression \( 6.3a*x+3a*y-x-y \).
Factor the expression by following steps:
- step0: Factor:
\(6.3ax+3ay-x-y\)
- step1: Convert the expressions:
\(\frac{63}{10}ax+3ay-x-y\)
- step2: Factor the expression:
\(\frac{1}{10}\left(63ax+30ay-10x-10y\right)\)
The fully factored form of the expression \(6.3ax + 3ay - x - y\) is \(\frac{1}{10}(63ax + 30ay - 10x - 10y)\).
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Bonus Knowledge
To factorise the expression \( 6.3 ax + 3ay - x - y \), we can start by grouping the terms. First, we can rearrange and group the terms related to \(a\) and those without: \[ (6.3 ax + 3ay) + (-x - y) \] Next, we can factor out common terms from each group. From the first group, we can factor out \(3a\): \[ 3a(2.1x + y) - (x + y) \] Now, we see that both parts have a common factor of \((2.1x + y)\): \[ (3a - 1)(2.1x + y) \] Thus, the fully factorised form of the given expression is: \[ (3a - 1)(2.1x + y) \]
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