Find the slope and \( y \)-intercept of the line. (If an answer does not exist, enter DNE.) \[ 4 x-5 y=20 \] slope \( y \)-intercept \( \quad(x, y)=(\square) \)

To find the slope and \( y \)-intercept from the equation \( 4x - 5y = 20 \), we can rearrange it into the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept. 1. Start by isolating \( y \): \[ -5y = -4x + 20 \] \[ y = \frac{4}{5}x - 4 \] From this, we see the slope \( m = \frac{4}{5} \) and the \( y \)-intercept \( b = -4 \). The \( y \)-intercept as an ordered pair is \( (0, -4) \). So the final answers are: slope: \( \frac{4}{5} \) \( y \)-intercept \( \quad(x, y)=(0, -4) \)