2. Here are the equations that define three functions. \( f(x)=6(x-3) \) a. Which function value is the largest: \( f(60), g(60) \), or \( h(60) \) ? What is thesvalue of the function? b. Which function value is the largest: \( f(-30), g(-30) \), or \( h(-30) \) ? What is the value of the function?

To find the largest function value for both parts, we first need the explicit definitions of \( g(x) \) and \( h(x) \) to perform the calculations. Assuming \( g(x) = 5x + 7 \) and \( h(x) = 4x - 2 \): a. For \( f(60) \), we have \( f(60) = 6(60 - 3) = 6(57) = 342 \). Calculating \( g(60) = 5(60) + 7 = 300 + 7 = 307 \) and \( h(60) = 4(60) - 2 = 240 - 2 = 238 \). Therefore, \( f(60) = 342 \) is the highest value. b. For \( f(-30) \), we calculate \( f(-30) = 6(-30 - 3) = 6(-33) = -198 \). Next, \( g(-30) = 5(-30) + 7 = -150 + 7 = -143 \) and \( h(-30) = 4(-30) - 2 = -120 - 2 = -122 \). Thus, the largest value is \( g(-30) = -143 \).