d)

To solve , we can use integration by parts or look for a suitable substitution. A common approach is to use the substitution , which gives or . Then, our integral transforms into . This integral can be solved by employing integration by parts, where you can let and .

The final expression for will involve the original variable back from using . After applying integration techniques, you can express the result in terms of and the integration constants. Remember that details and constants will matter, so keep track of your calculations!