Find the sum. \( -5 \frac{1}{3}+2 \frac{2}{3}=\square \)

To solve \(-5 \frac{1}{3} + 2 \frac{2}{3}\), we first convert the mixed numbers into improper fractions. For \(-5 \frac{1}{3}\): \[ -5 \frac{1}{3} = -\left(5 \times 3 + 1\right)/3 = -\frac{16}{3} \] For \(2 \frac{2}{3}\): \[ 2 \frac{2}{3} = (2 \times 3 + 2)/3 = \frac{8}{3} \] Now we add them together: \[ -\frac{16}{3} + \frac{8}{3} = \frac{-16 + 8}{3} = \frac{-8}{3} \] To convert \(\frac{-8}{3}\) back into a mixed number: \(-8 \div 3 = -2\) remainder \(-2\), which gives us: \[ -\frac{8}{3} = -2 \frac{2}{3} \] So the final sum is: \(-5 \frac{1}{3} + 2 \frac{2}{3} = -2 \frac{2}{3}\). Now, filling in the square, we get: -2 \frac{2}{3}