1. \( 4 \frac{4}{8}-2 \frac{16}{19}= \)
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To solve \( 4 \frac{4}{8}-2 \frac{16}{19} \), first convert the mixed numbers into improper fractions. For \( 4 \frac{4}{8} \): \( 4 \times 8 + 4 = 32 + 4 = 36 \) So, \( 4 \frac{4}{8} = \frac{36}{8} = \frac{9}{2} \) after simplifying. For \( 2 \frac{16}{19} \): \( 2 \times 19 + 16 = 38 + 16 = 54 \) So, \( 2 \frac{16}{19} = \frac{54}{19} \). Now, we need a common denominator to subtract these fractions. The least common denominator of 2 and 19 is 38. Converting both fractions: \( \frac{9}{2} = \frac{9 \times 19}{2 \times 19} = \frac{171}{38} \) \( \frac{54}{19} = \frac{54 \times 2}{19 \times 2} = \frac{108}{38} \) Now we can subtract: \( \frac{171}{38} - \frac{108}{38} = \frac{171 - 108}{38} = \frac{63}{38} \). Thus, \( 4 \frac{4}{8} - 2 \frac{16}{19} = \frac{63}{38} \) or \( 1 \frac{25}{38} \) if you convert it back to a mixed number.