13) Is \( (2,7) \) a solution to this system of equations? \( \begin{array}{l}6 x+y=16 \\ 3 x+2 y=20\end{array} \) 4) yes no

To determine if \( (2,7) \) is a solution, we can substitute \( x = 2 \) and \( y = 7 \) into both equations. For the first equation, \( 6(2) + 7 = 12 + 7 = 19 \), which does not equal 16. For the second equation, \( 3(2) + 2(7) = 6 + 14 = 20 \), which is correct. However, both equations need to be satisfied for \( (2,7) \) to be a solution. Since the first equation isn't satisfied, the answer is no. Now, let’s spice it up! Imagine if this system of equations were a duo at a dance party. One partner (the first equation) is clearly out of sync and just can't follow the beat, while the other (the second equation) is doing perfectly fine! It’s a classic case of a mismatched dance-off! So, no, \( (2,7) \) can't groove with this system!