Solve \( 3(x-7)-4=6(x+8) \) for \( x \) \( x=\square \)

To solve the equation \( 3(x-7)-4=6(x+8) \), let's simplify and isolate \( x \). 1. Distribute the \( 3 \) and \( 6 \): \[ 3x - 21 - 4 = 6x + 48 \] Simplifying gives: \[ 3x - 25 = 6x + 48 \] 2. Now, let's move all the \( x \) terms to one side and the constants to the other: \[ 3x - 6x = 48 + 25 \] This simplifies to: \[ -3x = 73 \] 3. Divide both sides by \( -3 \): \[ x = -\frac{73}{3} \] Hence, the solution is \( x = -\frac{73}{3} \).