Question 22 The amount of money in a CD account grows according to the equation $$ A(t)=5000(1.1)^{t} $$, where $$ A(t) $$ represents the amount after $$ t $$ years. Which of the following amount is possible after 10 years? $$ \$ 13,968.71 $$ $$ \$ 11,893.35 $$ $$ \$ 10,000 $$ $$ \$ 12,968.71 $$

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To determine the amount of money in the CD account after 10 years, we use the given formula:

$$ A(t) = 5000 \times (1.1)^t $$

Substituting $$ t = 10 $$:

$$ A(10) = 5000 \times (1.1)^{10} $$

First, calculate $$ (1.1)^{10} $$:

$$
\begin{align*}
1.1^1 & = 1.10 \
1.1^2 & = 1.21 \
1.1^3 & = 1.331 \
1.1^4 & = 1.4641 \
1.1^5 & = 1.61051 \
1.1^6 & = 1.771561 \
1.1^7 & = 1.9487171 \
1.1^8 & = 2.14358881 \
1.1^9 & = 2.357947691 \
1.1^{10} & = 2.5937424601 \
\end{align*}
$$

Now, multiply by 5000:

$$
A(10) = 5000 \times 2.5937424601 \approx 12,968.71
$$

**Therefore, the possible amount after 10 years is:**

$$\$12,968.71$$

**Answer:** $12,968.71
After 10 years, the amount in the CD account is \$12,968.71.

Question 22 The amount of money in a CD account grows according to the equation \( A(t)=5000(1.1)^{t} \), where \( A(t) \) represents the amount after \( t \) years. Which of the following amount is possible after 10 years? \( \$ 13,968.71 \) \( \$ 11,893.35 \) \( \$ 10,000 \) \( \$ 12,968.71 \)

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