Responder
To simplify the expression \( \sin^{2} \theta \) within \( \left(180^{\circ} - \theta\right) \cos \left(90^{\circ} + \theta\right) + \tan \theta \), follow these steps:
1. **Simplify \( \cos(90^{\circ} + \theta) \):**
\[
\cos(90^{\circ} + \theta) = -\sin \theta
\]
2. **Substitute back into the original expression:**
\[
\left(180^{\circ} - \theta\right) (-\sin \theta) + \tan \theta = -\left(180^{\circ} - \theta\right) \sin \theta + \tan \theta
\]
3. **Express \( \tan \theta \) in terms of sine and cosine:**
\[
\tan \theta = \frac{\sin \theta}{\cos \theta}
\]
4. **Combine like terms if possible:**
\[
-\left(180^{\circ} - \theta\right) \sin \theta + \frac{\sin \theta}{\cos \theta}
\]
5. **Factor out \( \sin \theta \) if needed:**
\[
\sin \theta \left[ -\left(180^{\circ} - \theta\right) + \frac{1}{\cos \theta} \right]
\]
6. **Use the identity \( \sin^2 \theta = \frac{1 - \cos(2\theta)}{2} \) if necessary for further simplification.**
**Final Simplified Expression:**
\[
\sin \theta \left[ -\left(180^{\circ} - \theta\right) + \frac{1}{\cos \theta} \right]
\]
This expression relates \( \sin^{2} \theta \) within the given trigonometric context.
Solución
Hello! It looks like you're working with some trigonometric expressions involving \( \sin^2 \theta \), \( \cos(90^{\circ} + \theta) \), and \( \tan \). However, the expression you've provided seems incomplete or a bit unclear. Let me try to interpret and assist you based on what you've shared.
### Provided Expression
You wrote:
\[
\sin^{2} \theta \quad \text{in} \quad \left(180^{\circ} - \theta\right) \cos \left(90^{\circ} + \theta\right) + \tan
\]
### Possible Interpretation
It appears you might be looking to simplify or relate the expression \( \sin^2 \theta \) within or in relation to the following trigonometric expression:
\[
\left(180^{\circ} - \theta\right) \cos \left(90^{\circ} + \theta\right) + \tan \theta
\]
*(Assuming that \( \tan \) is \( \tan \theta \))*
### Let's Break It Down
1. **Simplify \( \cos(90^{\circ} + \theta) \):**
Using the cosine addition formula:
\[
\cos(90^{\circ} + \theta) = -\sin \theta
\]
So, the expression becomes:
\[
\left(180^{\circ} - \theta\right) (-\sin \theta) + \tan \theta = -\left(180^{\circ} - \theta\right) \sin \theta + \tan \theta
\]
2. **Understanding the Angle Measurement:**
Notably, \( 180^{\circ} - \theta \) is an angle, but multiplying it directly by \( \sin \theta \) (which is dimensionless) is unconventional unless there's specific context, such as in a physical application where angles might be related to lengths or other quantities.
3. **Relating to \( \sin^2 \theta \):**
If you're aiming to express \( \sin^2 \theta \) in terms of the given expression, we might need additional information or context. However, here's a common identity involving \( \sin^2 \theta \):
\[
\sin^2 \theta = \frac{1 - \cos(2\theta)}{2}
\]
This identity is often useful in simplifying expressions or solving equations involving \( \sin^2 \theta \).
4. **Including \( \tan \theta \):**
Recall that:
\[
\tan \theta = \frac{\sin \theta}{\cos \theta}
\]
Depending on your goal, you might want to express everything in terms of sine and cosine or use other identities to combine or simplify the terms.
### Seeking Clarification
To provide more accurate assistance, could you please clarify:
- **What is the complete expression or equation you're working with?**
- **What is the goal?** Are you trying to simplify, solve for \( \theta \), prove an identity, or something else?
- **Any additional context or constraints?** For example, is this related to a specific problem in geometry, physics, or another field?
Feel free to provide more details or correct any part of the expression if there's a typo. I'm here to help!
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