Pregunta
\begin{tabular}{l} Evaluate. \\ \( (-9)^{2}=\square \) \\ \( (-4)^{3}=\square \) \\ \hline\end{tabular}
Ask by Campbell Pierce. in the United States
Jan 24,2025
Solución de tutoría real
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\[
\begin{tabular}{l}
\hline
\textbf{Evaluate.} \\
\( (-9)^{2} = 81 \) \\
\( (-4)^{3} = -64 \) \\
\hline
\end{tabular}
\]
Solución
Sure, let's evaluate each expression and fill in the squares accordingly.
\[
\begin{tabular}{l}
\hline
\textbf{Evaluate.} \\
\( (-9)^{2} = 81 \) \\
\( (-4)^{3} = -64 \) \\
\hline
\end{tabular}
\]
**Explanation:**
1. **\( (-9)^{2} \):**
- Squaring a negative number results in a positive number.
- \( (-9) \times (-9) = 81 \)
2. **\( (-4)^{3} \):**
- Cubing a negative number retains the negative sign.
- \( (-4) \times (-4) \times (-4) = (-4) \times 16 = -64 \)
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The Deep Dive
The expression \( (-9)^{2} \) equals \( 81 \) because when you square a negative number, the result is positive: \((-9) \times (-9) = 81\). For \( (-4)^{3} \), the result is \( -64 \) since you multiply \(-4\) three times: \((-4) \times (-4) \times (-4) = -64\). So the completed table would look like this: \[ \begin{tabular}{l} Evaluate. \\ \( (-9)^{2}= 81 \) \\ \( (-4)^{3}= -64 \) \\ \hline \end{tabular} \]
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