2 Calculate the hydroryle ion concentration $$ (\mid \mathrm{OH}] $$ ) of each of the following solutions $$ \left[\mathrm{H}^{4}\right]\left[\mathrm{OH}^{+}\right]=10^{-14} \mathrm{~mol} \mathrm{dm}^{3} $$ $$ 32.1 \mathrm{pH}=3 $$

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To calculate the hydroxide ion concentration ($$ [\mathrm{OH}^-] $$) of each of the given solutions, we can use the relationship between pH and pOH, which is given by:

$$ \mathrm{pH} + \mathrm{pOH} = 14 $$

Given that $$ \mathrm{pH} = 3 $$, we can calculate the pOH using the formula above:

$$ \mathrm{pOH} = 14 - \mathrm{pH} = 14 - 3 = 11 $$

Now, we can calculate the hydroxide ion concentration ($$ [\mathrm{OH}^-] $$) using the formula:

$$ [\mathrm{OH}^-] = 10^{-\mathrm{pOH}} $$

Substitute the value of pOH into the formula to find the hydroxide ion concentration.
Calculate the value by following steps:
- step0: Calculate:
  $$10^{-11}$$
The hydroxide ion concentration ($$ [\mathrm{OH}^-] $$) of the solution with a pH of 3 is $$ 10^{-11} \, \text{mol/dm}^3 $$.
The hydroxide ion concentration of the solution with a pH of 3 is $$ 10^{-11} \, \text{mol/dm}^3 $$.

2 Calculate the hydroryle ion concentration ) of each of the following solutions

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