Find the value of $$ x $$ that makes each equation true. Homework Help $$ \begin{array}{lll} ext { a. }-4.9 x=9.8 & ext { b. } \frac{8}{21}=-\frac{2}{7} x & ext { c. } \frac{3}{5}+x=\frac{2}{3}\end{array} $$

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Find the value of $$ x $$ that makes each equation true. Homework Help $$ \begin{array}{lll}	ext { a. }-4.9 x=9.8 & 	ext { b. } \frac{8}{21}=-\frac{2}{7} x & 	ext { c. } \frac{3}{5}+x=\frac{2}{3}\end{array} $$

UpStudy AI · Accepted Answer

**a. Solving $$-4.9x = 9.8$$:**  
Divide both sides by $$-4.9$$ to isolate $$x$$:
$$
x = \frac{9.8}{-4.9} = -2
$$

**b. Solving $$\frac{8}{21} = -\frac{2}{7}x$$:**  
Multiply both sides by the reciprocal of $$-\frac{2}{7}$$, which is $$-\frac{7}{2}$$, to solve for $$x$$:
$$
x = \frac{8}{21} \times \left(-\frac{7}{2}\right) = -\frac{56}{42}
$$  
Simplify the fraction by dividing numerator and denominator by 14:
$$
x = -\frac{4}{3}
$$

**c. Solving $$\frac{3}{5} + x = \frac{2}{3}$$:**  
Subtract $$\frac{3}{5}$$ from both sides:
$$
x = \frac{2}{3} - \frac{3}{5}
$$  
Find the common denominator, which is 15:
$$
x = \frac{10}{15} - \frac{9}{15} = \frac{1}{15}
$$

Final answers:  
a. $$x = -2$$  
b. $$x = -\frac{4}{3}$$  
c. $$x = \frac{1}{15}$$
$$ x = -2 $$, $$ x = -\frac{4}{3} $$, $$ x = \frac{1}{15} $$

Find the value of that makes each equation true. Homework Help

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