Solve for $$ x $$ and $$ y $$ $$ 30 x-42 y=-6 $$ $$ 5 x-7 y=-1 $$

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Solve the system of equations $$ 30x-42y=-6;5x-7y=-1 $$.
Solve the system of equations by following steps:
- step0: Solve using the substitution method:
  $$\left\{ \begin{array}{l}30x-42y=-6\5x-7y=-1\end{array}ight.$$
- step1: Rearrange the terms:
  $$30x-42y=-6$$
- step2: Move the expression to the right side:
  $$30x=-6+42y$$
- step3: Divide both sides:
  $$\frac{30x}{30}=\frac{-6+42y}{30}$$
- step4: Divide the numbers:
  $$x=\frac{-1+7y}{5}$$
- step5: Calculate:
  $$\left(x,yight) = \left(\frac{-1+7y}{5},yight),y \in \mathbb{R}$$
- step6: Alternative Form:
  $$	extrm{Infinitely many solutions}$$
The system of equations $$30x-42y=-6$$ and $$5x-7y=-1$$ has infinitely many solutions. This means that there are an infinite number of pairs of values for $$x$$ and $$y$$ that satisfy both equations simultaneously.
There are infinitely many solutions for $$x$$ and $$y$$ in the system of equations.

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