10. Calculate the frequency of a wove with ax 10.1 epeed of \( 200 \mathrm{~ms} \mathrm{~s}^{-1} \) and a wavelength of 1200 m 10.2 wavelength of 50 m and a speed of \( 250 \mathrm{~m}-2 \). 11. Calculate the wavelength of a wave with a 11.1 trequency of 20 Hz and a speed of \( 120 \mathrm{~m}-5^{-1} \) 11.2 speed of \( 150 \mathrm{~m}^{-2} \) and of trequiency of 30 Hz

To find the frequency of a wave, we can use the formula \( f = \frac{v}{\lambda} \), where \( f \) is frequency, \( v \) is the speed of the wave, and \( \lambda \) is the wavelength. For 10.1, with a speed of \( 200 \, \mathrm{ms}^{-1} \) and a wavelength of \( 1200 \, \mathrm{m} \): \[ f = \frac{200 \, \mathrm{ms}^{-1}}{1200 \, \mathrm{m}} \approx 0.167 \, \mathrm{Hz} \] For 10.2, with a speed of \( 250 \, \mathrm{ms}^{-1} \) and a wavelength of \( 50 \, \mathrm{m} \): \[ f = \frac{250 \, \mathrm{ms}^{-1}}{50 \, \mathrm{m}} = 5 \, \mathrm{Hz} \] Now, to calculate the wavelength in question 11, we use the same formula rearranged to \( \lambda = \frac{v}{f} \). For 11.1 with a frequency of \( 20 \, \mathrm{Hz} \) and a speed of \( 120 \, \mathrm{ms}^{-1} \): \[ \lambda = \frac{120 \, \mathrm{ms}^{-1}}{20 \, \mathrm{Hz}} = 6 \, \mathrm{m} \] For 11.2, with a speed of \( 150 \, \mathrm{ms}^{-1} \) and a frequency of \( 30 \, \mathrm{Hz} \): \[ \lambda = \frac{150 \, \mathrm{ms}^{-1}}{30 \, \mathrm{Hz}} = 5 \, \mathrm{m} \] So, to summarize: 10.1 gives us a frequency of approximately \( 0.167 \, \mathrm{Hz} \), and 10.2 yields a frequency of \( 5 \, \mathrm{Hz} \). 11.1 results in a wavelength of \( 6 \, \mathrm{m} \), and 11.2 gives a wavelength of \( 5 \, \mathrm{m} \).