Responder
Two events are independent in probability if the occurrence of one does not affect the probability of the other occurring.
Solución
In probability theory, **independence** between two events implies that the occurrence or non-occurrence of one event does not influence the probability of the other event occurring. In other words, knowing that one event has happened provides no information about whether the other event will happen.
### Mathematical Definition
For two events \( A \) and \( B \) in a probability space, they are **independent** if and only if:
\[
P(A \cap B) = P(A) \times P(B)
\]
Where:
- \( P(A \cap B) \) is the probability that both events \( A \) and \( B \) occur simultaneously.
- \( P(A) \) is the probability of event \( A \) occurring.
- \( P(B) \) is the probability of event \( B \) occurring.
### Equivalent Conditions
Independence can also be expressed using conditional probabilities:
1. **Conditional Probability Based Definitions:**
\[
P(A \mid B) = P(A) \quad \text{and} \quad P(B \mid A) = P(B)
\]
This means the probability of \( A \) occurring given that \( B \) has occurred is just \( P(A) \), and vice versa.
2. **No Influence:**
The occurrence of \( A \) does not affect the likelihood of \( B \) occurring, and the occurrence of \( B \) does not affect the likelihood of \( A \) occurring.
### Example
**Independent Events:**
- **Coin Tossing:** Consider tossing a fair coin twice. Let:
- \( A \) = "First toss is Heads."
- \( B \) = "Second toss is Heads."
The outcome of the first toss doesn't affect the outcome of the second toss. Here:
\[
P(A) = \frac{1}{2}, \quad P(B) = \frac{1}{2}, \quad P(A \cap B) = \frac{1}{4} = P(A) \times P(B)
\]
Thus, \( A \) and \( B \) are independent.
**Dependent Events:**
- **Drawing Cards Without Replacement:** Suppose you have a standard deck of 52 cards.
- \( A \) = "First card drawn is an Ace."
- \( B \) = "Second card drawn is an Ace."
If the first card drawn is an Ace (event \( A \) occurs), the probability of event \( B \) changes because there are now fewer Aces and fewer total cards. Here:
\[
P(A) = \frac{4}{52}, \quad P(B \mid A) = \frac{3}{51} \neq P(B) = \frac{4}{52}
\]
Therefore, \( A \) and \( B \) are **not** independent.
### Importance of Independence
Understanding whether events are independent is crucial in various fields, including statistics, finance, engineering, and computer science. It simplifies the computation of joint probabilities and is foundational in concepts like independent trials, Bayesian networks, and probabilistic modeling.
### Key Takeaways
- **Independence** means one event does not affect the probability of another.
- Use \( P(A \cap B) = P(A) \times P(B) \) to test for independence.
- Independent events have no influence on each other’s occurrence.
If you have any further questions or need clarification on related topics, feel free to ask!
Revisado y aprobado por el equipo de tutoría de UpStudy
Explicar
Simplifique esta solución