Find all complex number solutions to the equation. $$ x^{3}-512=0 $$ A. $$ \left\{4\left(\cos 0^{\circ}+i \sin 0^{\circ}\right), 4\left(\cos 120^{\circ}+i \sin 120^{\circ}\right), 4\left(\cos 240^{\circ}+i \sin 240^{\circ}\right)\right\} $$ B. $$ \left\{8\left(\cos 0^{\circ}+i \sin 0^{\circ}\right), 8\left(\cos 120^{\circ}+i \sin 120^{\circ}\right), 8\left(\cos 240^{\circ}+i \sin 240^{\circ}\right)\right\} $$ C. $$ \left\{4\left(\cos 60^{\circ}+i \sin 60^{\circ}\right), 4\left(\cos 180^{\circ}+i \sin 180^{\circ}\right), 4\left(\cos 300^{\circ}+i \sin 300^{\circ}\right)\right\} $$ D. $$ \left\{8\left(\cos 60^{\circ}+i \sin 60^{\circ}\right), 8\left(\cos 180^{\circ}+i \sin 180^{\circ}\right), 8\left(\cos 300^{\circ}+i \sin 300^{\circ}\right)\right\} $$ Correct solution set below.

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Solve the equation $$ x^{3}-512=0 $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$x^{3}-512=0$$
- step1: Move the constant to the right side:
  $$x^{3}=0+512$$
- step2: Remove 0:
  $$x^{3}=512$$
- step3: Simplify the equation:
  $$\sqrt[3]{x^{3}}=\sqrt[3]{512}$$
- step4: Calculate:
  $$x=\sqrt[3]{512}$$
- step5: Evaluate:
  $$x=8$$
The complex number solutions to the equation $$x^{3}-512=0$$ are $$x=8$$.

Therefore, the correct solution set is B. $$ \left\{8\left(\cos 0^{\circ}+i \sin 0^{\circ}\right), 8\left(\cos 120^{\circ}+i \sin 120^{\circ}\right), 8\left(\cos 240^{\circ}+i \sin 240^{\circ}\right)\right\} $$
The correct solution set is B.

Find all complex number solutions to the equation.

A.
B.
C.
D.
Correct solution set below.

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Find all complex number solutions to the equation. A. B. C. D. Correct solution set below.