Chapter 3 HW-Probability Topics + À Category: Homework Consider the following scenario: Let \( \mathrm{P}(C)=0.4 \). Let \( \mathrm{P}(D)=0.7 \). Let \( \mathrm{P}(C \mid D)=0.32 \). Note: Give your answers in their exact decimal forms. (a) FindP \( (C \) AND \( D) \). \[ \mathrm{P}(C \mathrm{AND} D)=0.224 \] (b) Are \( C \) and \( D \) mutually exclusive? Why or why not? A \( C \) and \( D \) are not mutually exclusive because \( \mathrm{P}(C \mid D) \neq \mathrm{P}(C)+\mathrm{P}(D) \). B \( C \) and \( D \) are not mutually exclusive because \( \mathrm{P}(C \) AND \( D) \neq 0 \). C \( C \) and \( D \) are mutually exclusive because \( \mathrm{P}(C \) AND \( D)=0 \). D \( C \) and \( D \) are mutually exclusive because \( \mathrm{P}(C)>\mathrm{P}(C \mid D) \). 2. Your answer is correct.
Solución de tutoría real
Responder
Solución
¡Inicia sesión para desbloquear respuestas gratis!
Una plataforma de aprendizaje en la que confían millones de estudiantes y profesores reales.
Revisado y aprobado por el equipo de tutoría de UpStudy
The Deep Dive
In probability, two events are mutually exclusive if they cannot occur at the same time. In this scenario, since \( \mathrm{P}(C \mathrm{AND} D) \) is not equal to 0, option B is the correct choice because it confirms that \( C \) and \( D \) can occur together. Just think about it: if \( C \) couldn’t happen when \( D \) happens, we wouldn’t have a positive probability for both! Now, let’s throw in some real-world application! Understanding whether events are mutually exclusive or not can be crucial in various fields such as finance and healthcare. For example, in a clinical trial, if two potential treatments (let's call them Treatment A and Treatment B) are mutually exclusive, no patient could respond to both treatments simultaneously. In contrast, if they can co-occur, evaluating their impacts becomes much more complex but also potentially more informative!