h. \( 18 \frac{3}{8}+2 \frac{2}{5}= \)

To tackle this problem, let's first convert the mixed numbers into improper fractions. For \( 18 \frac{3}{8} \), we multiply 18 by 8, which gives us 144, and then add 3, resulting in \( \frac{147}{8} \). For \( 2 \frac{2}{5} \), we multiply 2 by 5, giving us 10, then add 2, resulting in \( \frac{12}{5} \). Next, we need a common denominator to add these fractions, which is 40. We convert \( \frac{147}{8} \) to \( \frac{735}{40} \) and \( \frac{12}{5} \) to \( \frac{96}{40} \). Adding these gives us \( \frac{831}{40} \). This simplifies to \( 20 \frac{31}{40} \). Ultimately, \( 18 \frac{3}{8} + 2 \frac{2}{5} = 20 \frac{31}{40} \).