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\( \begin{array}{l}\text { When sodium hydrogencarbonate is heated, it decomposes to produce sodium carbonate, water } \\ \text { and carbon dioxide. } \\ \text { The equation for the reaction is } \\ \left.\text { [ } \mathrm{A}_{\mathrm{r}}: \mathrm{H}, 1 ; \mathrm{C}, 12 ; \mathrm{O}, 16 ; \mathrm{Na}_{3} 23\right] \\ \text { The relative molecular mass of sodium hydrogencarbonate is } 84 . \\ \text { (a) (i) Calculate the relative molecular mass of sodium carbonate. } \\ \text { (ii) Complete the following sentences. } \\ \text { (i) } \\ 4.2 \mathrm{~g} \text {. } \mathrm{CO} \\ 3\end{array}+\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} \).

Ask by Stewart Whittaker. in Brunei
Jan 22,2025

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The relative molecular mass of sodium carbonate is 106 g/mol.

Solución

To solve the problem, we will follow the steps outlined in the prompt. ### Step 1: Extract Known Conditions - The reaction involves sodium hydrogencarbonate decomposing into sodium carbonate, water, and carbon dioxide. - The relative atomic masses (A_r) are given as: - H: 1 - C: 12 - O: 16 - Na: 23 - The relative molecular mass of sodium hydrogencarbonate (NaHCO₃) is 84 g/mol. ### Step 2: Calculate the Relative Molecular Mass of Sodium Carbonate Sodium carbonate (Na₂CO₃) consists of: - 2 Sodium (Na) - 1 Carbon (C) - 3 Oxygen (O) Using the relative atomic masses, we can calculate the relative molecular mass of sodium carbonate: \[ \text{Relative Molecular Mass of Na}_2\text{CO}_3 = 2 \times \text{A}_r(\text{Na}) + 1 \times \text{A}_r(\text{C}) + 3 \times \text{A}_r(\text{O}) \] Substituting the values: \[ \text{Relative Molecular Mass of Na}_2\text{CO}_3 = 2 \times 23 + 1 \times 12 + 3 \times 16 \] Now, let's calculate this step by step: 1. Calculate \(2 \times 23\): \[ 2 \times 23 = 46 \] 2. Calculate \(1 \times 12\): \[ 1 \times 12 = 12 \] 3. Calculate \(3 \times 16\): \[ 3 \times 16 = 48 \] 4. Now, sum these results: \[ 46 + 12 + 48 = 106 \] Thus, the relative molecular mass of sodium carbonate (Na₂CO₃) is \(106\) g/mol. ### Step 3: Complete the Sentences The problem states: - "4.2 g CO₃ + CO₂ + H₂O" This indicates that 4.2 g of sodium hydrogencarbonate decomposes to produce sodium carbonate, carbon dioxide, and water. ### Final Answers (a) (i) The relative molecular mass of sodium carbonate is \(106\) g/mol. (ii) The completed sentence is: "4.2 g of sodium hydrogencarbonate decomposes to produce sodium carbonate, carbon dioxide, and water."

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The Deep Dive

To find the relative molecular mass of sodium carbonate (Na₂CO₃), we add the atomic masses of all its elements: sodium (Na) has an atomic mass of 23, carbon (C) has an atomic mass of 12, and oxygen (O) has an atomic mass of 16. Sodium carbonate consists of two sodium atoms, one carbon atom, and three oxygen atoms: \[ \text{Relative molecular mass of Na}_2\text{CO}_3 = (2 \times 23) + (1 \times 12) + (3 \times 16) = 46 + 12 + 48 = 106 \] So, the relative molecular mass of sodium carbonate is 106 g/mol. Now, about common mistakes: many students forget to multiply the atomic masses by the number of atoms present in the compound. For instance, when calculating the mass of water produced, it’s critical to remember that each water molecule (H₂O) contains 2 hydrogens (1 g each) and 1 oxygen (16 g), leading to a total of 18 g/mol for water. Double-checking your steps can save you from these simple errors!

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