Question 11 A rifle fie a bullet at a target 50 m away. It takes 0.06 seconds for the bullet to get to the target. How far will the bullet have fallen in that fime? pts th

To determine how far the bullet will have fallen during its flight to the target, we'll analyze the motion in two dimensions: horizontal and vertical. ### Given: - **Horizontal distance (Range)**: \( R = 50 \) meters - **Time of flight**: \( t = 0.06 \) seconds - **Acceleration due to gravity**: \( g = 9.8 \, \text{m/s}^2 \) ### Assumptions: - The rifle is fired **horizontally**, so the initial vertical velocity is \( 0 \). - Air resistance is negligible. ### Vertical Motion Analysis: Since there's no initial vertical velocity, the bullet's vertical displacement (\( y \)) is solely due to gravity. The formula for vertical displacement under constant acceleration is: \[ y = \frac{1}{2} g t^2 \] Plugging in the values: \[ y = \frac{1}{2} \times 9.8 \, \text{m/s}^2 \times (0.06 \, \text{s})^2 \] \[ y = 4.9 \, \text{m/s}^2 \times 0.0036 \, \text{s}^2 \] \[ y = 0.01764 \, \text{meters} \] \[ y \approx 1.76 \, \text{centimeters} \] ### Conclusion: The bullet will have fallen approximately **1.76 centimeters** during its 0.06-second flight to the target 50 meters away. **Answer:** The bullet falls approximately 1.76 centimeters during its 0.06-second flight.