If a $$ 45^{\circ}-45^{\circ}-90^{\circ} $$ triangle has a hypotenuse of 7.07 , find the length of each leg. (Round your answer to the nearest whole number.) Answer:

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In a $$ 45^{\circ}-45^{\circ}-90^{\circ} $$ triangle, the legs are congruent, and the hypotenuse is $$ \sqrt{2} $$ times the length of each leg.

Let $$ x $$ be the length of each leg. Then:
$$
\text{Hypotenuse} = x\sqrt{2}
$$
Given the hypotenuse is 7.07:
$$
x\sqrt{2} = 7.07
$$
$$
x = \frac{7.07}{\sqrt{2}} \approx \frac{7.07}{1.4142} \approx 5
$$

**Answer:** Each leg is approximately 5 units long.
Each leg is approximately 5 units long.

If a triangle has a hypotenuse of 7.07 , find the
length of each leg. (Round your answer to the nearest whole
number.)
Answer:

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If a triangle has a hypotenuse of 7.07 , find the length of each leg. (Round your answer to the nearest whole number.) Answer: