Rewrite the fol \[ \left(\frac{5}{3}\right)^{-2} \]

To rewrite \(\left(\frac{5}{3}\right)^{-2}\), we can apply the rule of negative exponents, which states that \(a^{-n} = \frac{1}{a^n}\). Therefore, we have: \[ \left(\frac{5}{3}\right)^{-2} = \frac{1}{\left(\frac{5}{3}\right)^{2}} \] Now, squaring the fraction gives us: \[ \left(\frac{5}{3}\right)^{2} = \frac{5^2}{3^2} = \frac{25}{9} \] Thus, we can rewrite our original expression: \[ \frac{1}{\left(\frac{5}{3}\right)^{2}} = \frac{1}{\frac{25}{9}} = \frac{9}{25} \] So, \(\left(\frac{5}{3}\right)^{-2}\) simplifies to \(\frac{9}{25}\).