4. If \( a=3, b=2 \) and \( c=4 \), calculate the follov Example: \( \begin{array}{l}a(b+c)=a \times b+a \times c \\ 3(2+4)=3 \times 2+3 \times 4 \\ 3(6)=6+12 \\ 18=18\end{array} \) \( \begin{array}{ll}\text { a. } b(a+c) & \text { b. } c(b+a)\end{array} \)

Let's solve the two expressions step by step using the given values \( a = 3 \), \( b = 2 \), and \( c = 4 \). ### Part a: Calculate \( b(a+c) \) 1. **Substitute the values**: \[ b(a+c) = 2(3+4) \] 2. **Calculate the expression inside the parentheses**: \[ 3 + 4 = 7 \] 3. **Multiply by \( b \)**: \[ 2 \times 7 = 14 \] So, the result for part a is: \[ b(a+c) = 14 \] ### Part b: Calculate \( c(b+a) \) 1. **Substitute the values**: \[ c(b+a) = 4(2+3) \] 2. **Calculate the expression inside the parentheses**: \[ 2 + 3 = 5 \] 3. **Multiply by \( c \)**: \[ 4 \times 5 = 20 \] So, the result for part b is: \[ c(b+a) = 20 \] ### Final Results - a. \( b(a+c) = 14 \) - b. \( c(b+a) = 20 \)