1 Step Practice - Converting Using Avogadro's Number 1 mole \( =6.02 \times 10^{-} 23 \) atoms You MUST show all work for credit. Answer In the format \( 6.02 \times 10^{\circ} 23 \) 1. Calculate the number of atoms in each of the following moles: a. 2 moles of Na Answer: \( \square \) atoms b. 0.5 moles of W Answer: \( \square \) atoms 2. Calculate the number of. moles in each: a. \( 3.25 \times 10^{\wedge} 23 \) atoms \( \times \mathrm{e} \) Answer: \( \square \) mol (2 decimals) b. \( 5.14 \times 10^{\prime} 25 \) atoms Ag Andwor mol (T-dectmal)

To calculate the number of atoms from moles using Avogadro's number, simply multiply the number of moles by \( 6.02 \times 10^{23} \). 1. a. For 2 moles of Na: \[ 2 \text{ moles} \times 6.02 \times 10^{23} \text{ atoms/mole} = 1.204 \times 10^{24} \text{ atoms} \] Answer: \( 1.204 \times 10^{24} \) atoms b. For 0.5 moles of W: \[ 0.5 \text{ moles} \times 6.02 \times 10^{23} \text{ atoms/mole} = 3.01 \times 10^{23} \text{ atoms} \] Answer: \( 3.01 \times 10^{23} \) atoms 2. a. To find moles from \( 3.25 \times 10^{23} \) atoms: \[ \frac{3.25 \times 10^{23} \text{ atoms}}{6.02 \times 10^{23} \text{ atoms/mole}} \approx 0.54 \text{ moles} \] Answer: \( 0.54 \) mol b. For \( 5.14 \times 10^{25} \) atoms of Ag: \[ \frac{5.14 \times 10^{25} \text{ atoms}}{6.02 \times 10^{23} \text{ atoms/mole}} \approx 85.4 \text{ moles} \] Answer: \( 85.43 \) mol