2. Write 720 as a product of it's prime factors

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To express **720** as a product of its prime factors, follow these steps:

1. **Divide by the smallest prime number (2):**
   - $$ 720 \div 2 = 360 $$
   - $$ 360 \div 2 = 180 $$
   - $$ 180 \div 2 = 90 $$
   - $$ 90 \div 2 = 45 $$
   
   So, we have $$ 2^4 $$ (since we divided by 2 four times).

2. **Next, divide by the next smallest prime number (3):**
   - $$ 45 \div 3 = 15 $$
   - $$ 15 \div 3 = 5 $$
   
   This gives us $$ 3^2 $$ (since we divided by 3 twice).

3. **Finally, what remains is 5, which is a prime number:**
   - $$ 5 \div 5 = 1 $$
   
   So, we have $$ 5^1 $$.

Putting it all together:
$$ 720 = 2^4 \times 3^2 \times 5 $$

**Prime Factorization of 720:**
$$ 720 = 2^4 \times 3^2 \times 5 $$
720 can be written as $$ 2^4 \times 3^2 \times 5 $$.

2. Write 720 as a product of it's prime factors

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