Responder
**5.2.2**
\( k(x) = -f(x) \)
**5.2.3 (a)**
\( t^{-1}(x) = \log_3(x - 2) + 1 \)
**5.2.3 (b)**
The function \( t(x) \) is obtained by shifting \( f(x) = 3^{x-1} + 2 \) **1 unit to the right** and **2 units up**.
Solución
Sure, let's address each part of your question step by step.
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### **5.2.2 If \( k(x) = -f(x) \), write down the equation of \( k \).**
**Answer:**
Given that \( k(x) \) is defined as the negative of \( f(x) \), the equation for \( k(x) \) is simply:
\[
k(x) = -f(x)
\]
*This means that for every value of \( x \), \( k(x) \) is the opposite of \( f(x) \). If \( f(x) \) outputs a positive value, \( k(x) \) will output a negative value of the same magnitude, and vice versa.*
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### **5.2.3 If \( f(x) = 3^{x-1} + 2 \) is translated to \( t \) such that \( t(x) = \ldots \)**
Let's assume that the translation involves transforming \( f(x) \) to \( t(x) \) by shifting it horizontally and/or vertically. Without additional specifics about the translation, we'll consider the standard form provided.
#### **(a) Determine \( t^{-1} \) in the form of \( y = \ldots \)**
**Answer:**
To find the inverse function \( t^{-1}(x) \), we need to solve for \( y \) in terms of \( x \) such that:
\[
y = t(x) = 3^{x-1} + 2
\]
**Steps to Find the Inverse:**
1. **Start with the original equation:**
\[
y = 3^{x-1} + 2
\]
2. **Subtract 2 from both sides:**
\[
y - 2 = 3^{x-1}
\]
3. **Apply the logarithm with base 3 to both sides to solve for \( x \):**
\[
\log_3(y - 2) = x - 1
\]
4. **Add 1 to both sides to isolate \( x \):**
\[
x = \log_3(y - 2) + 1
\]
5. **Swap \( x \) and \( y \) to express the inverse function:**
\[
t^{-1}(x) = \log_3(x - 2) + 1
\]
**So, the inverse function is:**
\[
t^{-1}(x) = \log_3(x - 2) + 1
\]
#### **(b) Describe the transformation from \( f \) to \( t \).**
**Answer:**
Given the original function \( f(x) = 3^{x-1} + 2 \), the transformation to \( t(x) \) involves the following steps:
1. **Horizontal Shift:**
- The term \( x - 1 \) inside the exponent indicates a **horizontal shift to the right by 1 unit**. This means that the graph of the exponential function \( 3^x \) is shifted rightward along the x-axis.
2. **Vertical Shift:**
- The \( +2 \) outside the exponent signifies a **vertical shift upward by 2 units**. This moves the entire graph of the function upward along the y-axis.
**Summary of the Transformation:**
- **Right Shift:** 1 unit
- **Upward Shift:** 2 units
*These combined shifts result in the graph of \( t(x) \) being positioned 1 unit to the right and 2 units above the original graph of \( 3^x \).*
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### **Visual Representation**
To better understand the transformation, here's a simplified visual representation:
- **Original Function \( 3^x \):** Starts at \( (0, 1) \).
- **After Shifting Right by 1:** Becomes \( 3^{x-1} \), starting at \( (1, 1) \).
- **After Shifting Up by 2:** Becomes \( 3^{x-1} + 2 \), starting at \( (1, 3) \).
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Feel free to ask if you need further clarification on any of these steps!
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