that $$ \left(\frac{1}{25} ight)^{x+1} imes 5^{6 x-3}=\frac{5}{5^{-x}} $$, find

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that $$ \left(\frac{1}{25}ight)^{x+1} 	imes 5^{6 x-3}=\frac{5}{5^{-x}} $$, find

UpStudy AI · Accepted Answer

Solve the equation $$ \left(\frac{1}{25}ight)^{x+1} 	imes 5^{6x-3}=\frac{5}{5^{-x}} $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$\left(\frac{1}{25}ight)^{x+1}	imes 5^{6x-3}=\frac{5}{5^{-x}}$$
- step1: Multiply the terms:
  $$5^{4x-5}=5^{x+1}$$
- step2: Set the exponents equal:
  $$4x-5=x+1$$
- step3: Move the expression to the left side:
  $$4x-x=1+5$$
- step4: Add and subtract:
  $$3x=1+5$$
- step5: Add and subtract:
  $$3x=6$$
- step6: Divide both sides:
  $$\frac{3x}{3}=\frac{6}{3}$$
- step7: Divide the numbers:
  $$x=2$$
The solution to the equation $$ \left(\frac{1}{25}ight)^{x+1} 	imes 5^{6x-3}=\frac{5}{5^{-x}} $$ is $$ x=2 $$.
$$ x=2 $$

that , find

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