$$ \overrightarrow{F H} $$ bisects $$ \angle E F G $$. Find the indicated angle measures. $$ m \angle G F H=71^{\circ} $$. Find $$ m \angle E F H $$ and $$ m \angle E F G $$. $$ m \angle E F H=\square^{\circ} $$ $$ m \angle E F G= $$

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Given that $$ \overrightarrow{FH} $$ bisects $$ \angle EFG $$, it means that $$ \overrightarrow{FH} $$ divides $$ \angle EFG $$ into two equal angles. Let's break this down step by step:

1. **Understanding the Bisector:**
   - $$ \overrightarrow{FH} $$ bisects $$ \angle EFG $$, so:
     $$
     \angle EFH = \angle HFG
     $$
   - Let’s denote each of these equal angles as $$ x $$. Therefore:
     $$
     \angle EFH = x \quad \text{and} \quad \angle HFG = x
     $$
   
2. **Given Information:**
   - It is given that:
     $$
     m\angle GFH = 71^\circ
     $$
   - Since $$ \angle GFH = \angle HFG = x $$, we have:
     $$
     x = 71^\circ
     $$
   
3. **Calculating $$ \angle EFG $$:**
   - The entire angle $$ \angle EFG $$ is the sum of $$ \angle EFH $$ and $$ \angle HFG $$:
     $$
     m\angle EFG = x + x = 2x = 2 \times 71^\circ = 142^\circ
     $$
   
4. **Summary of Angle Measures:**
   - $$ m\angle EFH = 71^\circ $$
   - $$ m\angle EFG = 142^\circ $$

**Final Answers:**
$$
m \angle EFH = 71^\circ
$$
$$
m \angle EFG = 142^\circ
$$

**Answer:**

$$ m \angle E F H = 71^{\circ} $$

$$ m \angle E F G = 142^{\circ} $$
$$ m \angle E F H = 71^\circ $$ $$ m \angle E F G = 142^\circ $$

\( \overrightarrow{F H} \) bisects \( \angle E F G \). Find the indicated angle measures. \( m \angle G F H=71^{\circ} \). Find \( m \angle E F H \) and \( m \angle E F G \). \( m \angle E F H=\square^{\circ} \) \( m \angle E F G= \)

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