Simplify a, $$ \frac{3.2^{2 x}-2^{x-4}}{2^{x}+2^{x+2}} $$

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Calculate or simplify the expression $$ (3.2^{2x}-2^{x-4})/(2^{x}+2^{x+2}) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{\left(3.2^{2x}-2^{x-4}ight)}{\left(2^{x}+2^{x+2}ight)}$$
- step1: Remove the parentheses:
  $$\frac{3.2^{2x}-2^{x-4}}{2^{x}+2^{x+2}}$$
- step2: Convert the expressions:
  $$\frac{\left(\frac{16}{5}ight)^{2x}-2^{x-4}}{2^{x}+2^{x+2}}$$
- step3: Add the terms:
  $$\frac{\left(\frac{16}{5}ight)^{2x}-2^{x-4}}{5	imes 2^{x}}$$
- step4: Expand the expression:
  $$\frac{\frac{16^{2x}-2^{x-4}	imes 5^{2x}}{5^{2x}}}{5	imes 2^{x}}$$
- step5: Multiply by the reciprocal:
  $$\frac{16^{2x}-2^{x-4}	imes 5^{2x}}{5^{2x}}	imes \frac{1}{5	imes 2^{x}}$$
- step6: Rewrite the expression:
  $$\frac{2^{x}\left(2^{7x}-2^{-4}	imes 5^{2x}ight)}{5^{2x}}	imes \frac{1}{5	imes 2^{x}}$$
- step7: Reduce the fraction:
  $$\frac{2^{7x}-2^{-4}	imes 5^{2x}}{5^{2x}}	imes \frac{1}{5}$$
- step8: Multiply the terms:
  $$\frac{2^{7x}-2^{-4}	imes 5^{2x}}{5^{2x}	imes 5}$$
- step9: Multiply the terms:
  $$\frac{2^{7x}-2^{-4}	imes 5^{2x}}{5^{2x+1}}$$
- step10: Simplify:
  $$\frac{2^{7x+4}-5^{2x}}{16	imes 5^{2x+1}}$$
The simplified expression is $$ \frac{2^{7x+4}-5^{2x}}{16 	imes 5^{2x+1}} $$.
Simplify the expression $$ \frac{3.2^{2x}-2^{x-4}}{2^{x}+2^{x+2}} $$ to $$ \frac{2^{7x+4}-5^{2x}}{16 	imes 5^{2x+1}} $$.

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