On the morning of the June 23,2000 , the MV Treasure - a bulk ore carrier - sank off the west coast of South Africa, causing a major oil spill. The MV Treasure had 1344 metric tonne of heavy fuel oil on board, as well as 56 metric tonne of marine diesel and 64 metric tonne of lubrication oil. All of this fuel except for 205 metric tonne of the heavy fuel oil ended up in the cean, in the area between Robben Island (near Cape Town) and Dassen Island off the coast of the West Coast National Park). How many tonne of fuel spilt into the ocean during this disaster? If one metric tonne is 1000 litres, convert the answer in \( 4 . a \) to litres. Convert the answer in \( 4 . b \) to cubic metres. ( 1 litre \( =1000 \mathrm{~cm}^{3} \) ) If this volume of fuel was to be poured into a rectangular prism with the base having the same dimensions as a soccer field, calculate the height of the volume of fuel in centimetres. (The dimensions of a soccer field are approximately 105 m by 69 m ; the volume of a rectangular prism \( = \) length \( \times \) width \( \times \) height.)
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To find out how many tonnes of fuel spilled into the ocean during the MV Treasure disaster, we start by calculating the total amount of fuel on board: - Total fuel = Heavy fuel oil + Marine diesel + Lubrication oil = 1344 + 56 + 64 = **1464 metric tonnes**. - Total fuel after the spill = 1464 metric tonnes - 205 metric tonnes = **1259 metric tonnes**. Now for the conversion to litres and cubic metres: 1. **Litres**: \( 1259 \, \text{metric tonnes} = 1259 \times 1000 = 1,259,000 \, \text{litres} \). 2. **Cubic metres**: To convert litres to cubic metres: \( 1,259,000 \, \text{litres} = 1,259 \, \text{cubic metres} \). Next, we calculate the height of the fuel spilled if it were poured into a rectangular prism with the dimensions of a soccer field. The area of the soccer field can be calculated as follows: - Area \( = \text{length} \times \text{width} = 105 \, \text{m} \times 69 \, \text{m} = 7245 \, \text{m}^2 \). Now, using the formula for the volume of a rectangular prism \( V = \text{length} \times \text{width} \times \text{height} \): - Rearranging this for height gives us \( \text{height} = \frac{V}{\text{length} \times \text{width}} \). Substituting in the values, we find the height in metres first: - Height \( = \frac{1259 \, \text{m}^3}{7245 \, \text{m}^2} \approx 0.174 \, \text{m} \). To convert this to centimetres (1 m = 100 cm): - Height \( = 0.174 \, \text{m} \times 100 = 17.4 \, \text{cm} \). So, the final answer for height of the fuel would be approximately **17.4 cm**.