\( \frac{-8+\sqrt{-20}}{24}=\square \) (Type an exact answer, using radicals as needed Type your answor in the form a bi

Let’s simplify the expression step by step: First, simplify the term \(\sqrt{-20}\). \[ \sqrt{-20} = \sqrt{20} \cdot i = \sqrt{4 \cdot 5} \cdot i = 2\sqrt{5} \cdot i \] Now, substitute this back into the original expression: \[ \frac{-8 + 2\sqrt{5}i}{24} \] Next, we can separate the real and imaginary parts: \[ = \frac{-8}{24} + \frac{2\sqrt{5}i}{24} = -\frac{1}{3} + \frac{\sqrt{5}}{12}i \] Thus, the final result is: \[ -\frac{1}{3} + \frac{\sqrt{5}}{12}i \] So in the form \( a + bi \), it is: \[ \boxed{-\frac{1}{3} + \frac{\sqrt{5}}{12}i} \]