3. $$ f(x)=\frac{x^{2}-3 x+5}{x+1} $$ હोય, तो $$ f(3), f(-2), f\left(\frac{1}{2}\right) $$ शोध

Question

UpStudy AI · Accepted Answer

દિધેલા ફંક્શન છે:

$$ f(x) = \frac{x^{2} - 3x + 5}{x + 1} $$

અપેક્ષિત મૂલ્યો શોધવા માટે, $$ f(3) $$, $$ f(-2) $$, અને $$ f\left(\frac{1}{2}\right) $$ ની ગણતરી કરીએ.

1. **$$ f(3) $$:**

$$
\begin{align*}
\text{સાંખ્યિક ભાગ} &= 3^{2} - 3 \times 3 + 5 = 9 - 9 + 5 = 5 \
\text{હિસ્સો} &= 3 + 1 = 4 \
f(3) &= \frac{5}{4}
\end{align*}
$$

2. **$$ f(-2) $$:**

$$
\begin{align*}
\text{સાંખ્યિક ભાગ} &= (-2)^{2} - 3 \times (-2) + 5 = 4 + 6 + 5 = 15 \
\text{હિસ્સો} &= -2 + 1 = -1 \
f(-2) &= \frac{15}{-1} = -15
\end{align*}
$$

3. **$$ f\left(\frac{1}{2}\right) $$:**

$$
\begin{align*}
\text{સાંખ્યિક ભાગ} &= \left(\frac{1}{2}\right)^{2} - 3 \times \frac{1}{2} + 5 = \frac{1}{4} - \frac{3}{2} + 5 \
&= \frac{1}{4} - \frac{6}{4} + \frac{20}{4} = \frac{15}{4} \
\text{હિસ્સો} &= \frac{1}{2} + 1 = \frac{3}{2} \
f\left(\frac{1}{2}\right) &= \frac{\frac{15}{4}}{\frac{3}{2}} = \frac{15}{4} \times \frac{2}{3} = \frac{30}{12} = \frac{5}{2}
\end{align*}
$$

**સારાંશ:**

- $$ f(3) = \frac{5}{4} $$
- $$ f(-2) = -15 $$
- $$ f\left(\frac{1}{2}\right) = \frac{5}{2} $$
$$ f(3) = \frac{5}{4} $$, $$ f(-2) = -15 $$, $$ f\left(\frac{1}{2}\right) = \frac{5}{2} $$.

3. \( f(x)=\frac{x^{2}-3 x+5}{x+1} \) હोય, तो \( f(3), f(-2), f\left(\frac{1}{2}\right) \) शोध

Solución de tutoría real

Responder

Solución

Mind Expander

preguntas relacionadas

Latest Algebra Questions