Pregunta
A line has a slope of -3 and passes through the point \( (4,-15) \). Write its equation in slope- intercept form. Write your answer using integers, proper fractions, and improper fractions in simplest form.
Ask by Schofield Adkins. in the United States
Jan 24,2025
Solución de tutoría real
Respuesta verificada por el tutor
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The equation of the line in slope-intercept form is \( y = -3x - 3 \).
Solución
The slope-intercept form of a line is given by:
\[
y = mx + b
\]
where \( m \) is the slope and \( b \) is the y-intercept.
Given:
- Slope (\( m \)) = -3
- The line passes through the point \( (4, -15) \).
First, substitute the slope and the coordinates of the point into the equation to solve for \( b \):
\[
-15 = (-3)(4) + b
\]
\[
-15 = -12 + b
\]
\[
b = -15 + 12
\]
\[
b = -3
\]
So, the equation of the line in slope-intercept form is:
\[
y = -3x - 3
\]
**Answer:**
\( y = -3x - 3 \)
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The Deep Dive
To find the equation of the line in slope-intercept form \( y = mx + b \), we start with the given slope \( m = -3 \) and the point \( (4, -15) \). We can substitute these values into the equation to find \( b \): \[ -15 = -3(4) + b \] \[ -15 = -12 + b \] \[ b = -15 + 12 = -3 \] Now we can write the equation of the line: \[ y = -3x - 3 \] So, the equation in slope-intercept form is \( y = -3x - 3 \).
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