You would like to have \( \$ 3,000 \) in 3 years for a special vacation following graduation by making deposits at the end of every six months in an annuity that pays \( 4 \% \) compounded semiannually. a. Determine how much you should deposit at the end of every six months. b. How much of the \( \$ 3,000 \) comes from deposits and how much comes from interest? a. In order to have \( \$ 3,000 \) in 3 years, you should deposit \( \$ \square \) at the end of every six months. (Do not round until the final answer. Then round up to the nearest dollar.) b. \( \$ \square \) of the \( \$ 3,000 \) comes from your deposits and \( \$ \square \) comes from interest. (Use the answer from part a to find this answer. Round to the nearest dollar as needed.) be
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Beyond the Answer
To solve this problem, we need to use the formula for the future value of an ordinary annuity. The formula is given by: \[ FV = P \times \frac{(1 + r)^n - 1}{r} \] Where: - \( FV \) is the future value of the annuity (which we want to be \( 3000 \)) - \( P \) is the amount deposited at the end of every period (which we're solving for) - \( r \) is the interest rate per period - \( n \) is the total number of periods In this case, since the interest is compounded semiannually, the interest rate \( r \) per period will be \( 0.04/2 = 0.02 \), and the total number of periods \( n \) is \( 3 \times 2 = 6 \). Now, we can substitute these values into the formula: \[ 3000 = P \times \frac{(1 + 0.02)^6 - 1}{0.02} \] Calculating \( (1 + 0.02)^6 \): \[ (1.02)^6 \approx 1.12616 \] Now plug this into the equation: \[ 3000 = P \times \frac{1.12616 - 1}{0.02} = P \times \frac{0.12616}{0.02} \approx P \times 6.308 \] Now solve for \( P \): \[ P \approx \frac{3000}{6.308} \approx 475.47 \] Thus, you would need to deposit approximately \( 475.47 \) at the end of every six months. Rounding up, you should deposit \( \$ 476 \). Now, to find out how much comes from deposits and how much from interest: Total deposits over 6 periods: \[ Total\, Deposits = P \times n = 476 \times 6 = 2856 \] Now subtract from the future value to find the interest earned: \[ Interest = 3000 - 2856 = 144 \] Thus, a. In order to have \( \$ 3,000 \) in 3 years, you should deposit \( \$ 476 \) at the end of every six months. b. \( \$ 2,856 \) of the \( \$ 3,000 \) comes from your deposits and \( \$ 144 \) comes from interest.