Responder
a. **Synthesis Reaction**
b. **Single-Displacement Reaction**
c. **Decomposition Reaction**
d. **Combustion Reaction**
e. **Decomposition Reaction**
f. **Synthesis Reaction**
g. **Double-Displacement Reaction**
Solución
Sure, let's classify each of the given chemical reactions based on their types:
### a. \( \mathrm{N}_2 + 3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3 \)
**Type:** **Synthesis Reaction**
**Explanation:** This reaction involves two reactants (\(\mathrm{N}_2\) and \(\mathrm{H}_2\)) combining to form a single product (\(\mathrm{NH}_3\)). Synthesis reactions typically involve the combination of simpler substances to form a more complex compound.
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### b. \( \mathrm{Li} + 2 \mathrm{H}_2\mathrm{O} \rightarrow 2 \mathrm{LiOH} + \mathrm{H}_2 \)
**Type:** **Single-Displacement Reaction**
**Explanation:** In this reaction, lithium (\(\mathrm{Li}\)) displaces hydrogen from water (\(\mathrm{H}_2\mathrm{O}\)) to form lithium hydroxide (\(\mathrm{LiOH}\)) and hydrogen gas (\(\mathrm{H}_2\)). Single-displacement reactions involve an element reacting with a compound, where one element replaces another in the compound.
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### c. \( 2 \mathrm{NaNO}_3 \rightarrow 2 \mathrm{NaNO}_2 + \mathrm{O}_2 \)
**Type:** **Decomposition Reaction**
**Explanation:** Sodium nitrate (\(\mathrm{NaNO}_3\)) breaks down into sodium nitrite (\(\mathrm{NaNO}_2\)) and oxygen gas (\(\mathrm{O}_2\)). Decomposition reactions involve a single compound breaking down into two or more simpler substances.
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### d. \( 2 \mathrm{C}_6\mathrm{H}_{14} + 19 \mathrm{O}_2 \rightarrow 12 \mathrm{CO}_2 + 14 \mathrm{H}_2\mathrm{O} \)
**Type:** **Combustion Reaction**
**Explanation:** This reaction involves a hydrocarbon (\(\mathrm{C}_6\mathrm{H}_{14}\)) reacting with oxygen (\(\mathrm{O}_2\)) to produce carbon dioxide (\(\mathrm{CO}_2\)) and water (\(\mathrm{H}_2\mathrm{O}\)). Combustion reactions typically involve organic compounds reacting with oxygen to produce carbon dioxide and water, often releasing energy in the form of heat and light.
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### e. \( \mathrm{NH}_4\mathrm{Cl} \rightarrow \mathrm{NH}_3 + \mathrm{HCl} \)
**Type:** **Decomposition Reaction**
**Explanation:** Ammonium chloride (\(\mathrm{NH}_4\mathrm{Cl}\)) decomposes into ammonia (\(\mathrm{NH}_3\)) and hydrogen chloride (\(\mathrm{HCl}\)). This is a classic example of a decomposition reaction where a single compound breaks down into multiple products.
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### f. \( \mathrm{BaO} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{Ba(OH)}_2 \)
**Type:** **Synthesis Reaction**
**Explanation:** Barium oxide (\(\mathrm{BaO}\)) reacts with water (\(\mathrm{H}_2\mathrm{O}\)) to form barium hydroxide (\(\mathrm{Ba(OH)}_2\)). This is a synthesis reaction where two reactants combine to form a single, more complex product.
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### g. \( \mathrm{AgNO}_3 + \mathrm{NaCl} \rightarrow \mathrm{AgCl} + \mathrm{NaNO}_3 \)
**Type:** **Double-Displacement Reaction**
**Explanation:** Silver nitrate (\(\mathrm{AgNO}_3\)) and sodium chloride (\(\mathrm{NaCl}\)) exchange their ions to form silver chloride (\(\mathrm{AgCl}\)) and sodium nitrate (\(\mathrm{NaNO}_3\)). Double-displacement reactions involve the exchange of ions between two compounds to form two new compounds.
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### **Summary:**
| **Reaction** | **Type** |
|-------------------------------------------------------|----------------------------|
| a. \( \mathrm{N}_2 + 3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3 \) | Synthesis Reaction |
| b. \( \mathrm{Li} + 2 \mathrm{H}_2\mathrm{O} \rightarrow 2 \mathrm{LiOH} + \mathrm{H}_2 \) | Single-Displacement Reaction |
| c. \( 2 \mathrm{NaNO}_3 \rightarrow 2 \mathrm{NaNO}_2 + \mathrm{O}_2 \) | Decomposition Reaction |
| d. \( 2 \mathrm{C}_6\mathrm{H}_{14} + 19 \mathrm{O}_2 \rightarrow 12 \mathrm{CO}_2 + 14 \mathrm{H}_2\mathrm{O} \) | Combustion Reaction |
| e. \( \mathrm{NH}_4\mathrm{Cl} \rightarrow \mathrm{NH}_3 + \mathrm{HCl} \) | Decomposition Reaction |
| f. \( \mathrm{BaO} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{Ba(OH)}_2 \) | Synthesis Reaction |
| g. \( \mathrm{AgNO}_3 + \mathrm{NaCl} \rightarrow \mathrm{AgCl} + \mathrm{NaNO}_3 \) | Double-Displacement Reaction |
If you have any further questions or need additional explanations, feel free to ask!
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