Write + or - in each $$ \bigcirc $$ to make each equation true. (a) $$ \frac{13}{18} \bigcirc \frac{1}{9} \bigcirc \frac{1}{2} \bigcirc \frac{2}{3}=1 $$

Question

UpStudy AI · Accepted Answer

To solve the equation by inserting $$ + $$ or $$ - $$ in each $$ \bigcirc $$, let's analyze the given equation:

$$
\frac{13}{18} \bigcirc \frac{1}{9} \bigcirc \frac{1}{2} \bigcirc \frac{2}{3} = 1
$$

**Step 1: Convert Fractions to Common Denominator**

First, express all fractions with a common denominator of 18:

$$
\frac{13}{18}, \quad \frac{1}{9} = \frac{2}{18}, \quad \frac{1}{2} = \frac{9}{18}, \quad \frac{2}{3} = \frac{12}{18}
$$

So the equation becomes:

$$
\frac{13}{18} \bigcirc \frac{2}{18} \bigcirc \frac{9}{18} \bigcirc \frac{12}{18} = 1
$$

**Step 2: Simplify the Equation**

Multiply the entire equation by 18 to eliminate the denominators:

$$
13 \bigcirc 2 \bigcirc 9 \bigcirc 12 = 18
$$

**Step 3: Determine the Operations**

We need to determine where to place $$ + $$ or $$ - $$ to satisfy the equation:

$$
13 + 2 - 9 + 12 = 18
$$

**Verification:**

$$
13 + 2 = 15 \
15 - 9 = 6 \
6 + 12 = 18
$$

**Conclusion:**

The correct placement of the operations is:

$$
\frac{13}{18} + \frac{1}{9} - \frac{1}{2} + \frac{2}{3} = 1
$$

**Final Answer:**

$$
\frac{13}{18} + \frac{1}{9} - \frac{1}{2} + \frac{2}{3} = 1
$$
$$ \frac{13}{18} + \frac{1}{9} - \frac{1}{2} + \frac{2}{3} = 1 $$

Write + or - in each to make each equation true.
(a)

Solución de inteligencia artificial de Upstudy

Responder

Solución

The Deep Dive

preguntas relacionadas

Latest Pre Algebra Questions

Write + or - in each to make each equation true. (a)