(5) Pesume ypabrerue: 1) \( (x-1)^{2}-(x+3)(x-3)=12 \) 2) \( (2 y-3)(5 y+1)+2(y-5)(y+5)=2(1-2 y)^{2}+6 y \)
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To tackle the equation \( (x-1)^{2}-(x+3)(x-3)=12 \), first expand both sides. The left side transforms into \( (x-1)^2 - (x^2 - 9) = 12 \), leading to \( x^2 - 2x + 1 - x^2 + 9 = 12 \). Simplify it to find \( -2x + 10 = 12 \), which provides \( x = -1 \) after moving terms around. Now, move on to the second equation \( (2 y-3)(5 y+1)+2(y-5)(y+5)=2(1-2 y)^{2}+6 y \). Expand the left: \( (10y^2 - 15y + 2y - 10) = 10y^2 - 13y - 10 \). The right side expands to yield \( 2(4y^2 - 4y + 1) + 6y = 8y^2 - 8y + 2 + 6y = 8y^2 - 2y + 2 \). Set both sides equal to each other and simplify to solve for \( y \). Now, let's see where these steps can lead us!