A) Fill in all missing terms and select all missing descriptions. Simplify any fractions. \begin{tabular}{rr|r|}\hline \( 6(12 p+3) \) & \( =3 p+18 \) & \\ \( 72 p+\square \) & \( =3 p+18 \) & \( \square \) \\ \( \square+18 \) & \( =18 \) & \( \square \) \\ \( 69 p \) & \( =\square \) \\ \( p \) & \( =\square \) & \( \square \) \\ \hline\end{tabular}

To fill in the missing terms and descriptions in the table, we will solve each equation step by step. 1. **First Row:** \[ 6(12p + 3) = 3p + 18 \] Distributing \(6\): \[ 72p + 18 = 3p + 18 \] Now, we can simplify this equation. Subtract \(3p\) from both sides: \[ 72p - 3p + 18 = 18 \] This simplifies to: \[ 69p + 18 = 18 \] 2. **Second Row:** \[ 72p + \square = 3p + 18 \] From the first row, we know that \(72p + 18 = 3p + 18\). Therefore, the missing term is \(18\). 3. **Third Row:** \[ \square + 18 = 18 \] To find the missing term, we can subtract \(18\) from both sides: \[ \square = 18 - 18 \] This gives us: \[ \square = 0 \] 4. **Fourth Row:** \[ 69p = \square \] From the previous calculations, we have \(69p = 0\) (since we found that the term from the third row is \(0\)). Therefore, the missing term is \(0\). 5. **Fifth Row:** \[ p = \square \] Since \(69p = 0\), we can solve for \(p\): \[ p = \frac{0}{69} = 0 \] Thus, the missing term is \(0\). Now, we can fill in the table with the missing terms: \[ \begin{tabular}{rr|r|}\hline \( 6(12 p+3) \) & \( =3 p+18 \) & \\ \( 72 p+18 \) & \( =3 p+18 \) & \( 18 \) \\ \( 0+18 \) & \( =18 \) & \( 0 \) \\ \( 69 p \) & \( =0 \) & \\ \( p \) & \( =0 \) & \( 0 \) \\ \hline \end{tabular} \] ### Summary of Missing Descriptions: - The first row has no missing description. - The second row has \(18\) as the missing term. - The third row has \(0\) as the missing term. - The fourth row has \(0\) as the missing term. - The fifth row has \(0\) as the missing term. Thus, all missing terms and descriptions have been filled in and simplified.