Find the product. Simplify your answer. $$ -3 s^{2}\left(2 s^{2}-s+1\right) $$

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To find the product of $$-3s^{2}$$ and $$(2s^{2} - s + 1)$$, follow these steps:

1. **Distribute $$-3s^{2}$$ to each term inside the parentheses:**
   $$
   -3s^{2} \times 2s^{2} + (-3s^{2}) \times (-s) + (-3s^{2}) \times 1
   $$

2. **Multiply the coefficients and add the exponents for each term:**
   - $$-3 \times 2 = -6$$ and $$s^{2} \times s^{2} = s^{4}$$:
     $$
     -6s^{4}
     $$
   - $$-3 \times (-1) = 3$$ and $$s^{2} \times s = s^{3}$$:
     $$
     +3s^{3}
     $$
   - $$-3 \times 1 = -3$$ and $$s^{2}$$ remains:
     $$
     -3s^{2}
     $$

3. **Combine all the terms:**
   $$
   -6s^{4} + 3s^{3} - 3s^{2}
   $$

**Final Answer:**
$$
-6s^{4} + 3s^{3} - 3s^{2}
$$
$$ -6s^{4} + 3s^{3} - 3s^{2} $$

Find the product. Simplify your answer. \( -3 s^{2}\left(2 s^{2}-s+1\right) \)

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