The function $$ h(x)=\frac{1}{x+1} $$ can be expressed in the form $$ f(g(x)) $$, where $$ g(x)=(x+1) $$, and $$ f(x) $$ is defined as: $$ f(x)=\square $$

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To express the function $$ h(x) = \frac{1}{x+1} $$ in the form $$ f(g(x)) $$, where $$ g(x) = x + 1 $$, we need to determine the appropriate function $$ f(x) $$.

Given:
$$
h(x) = \frac{1}{x + 1} = f(g(x)) = f(x + 1)
$$

To find $$ f(x) $$, we set:
$$
f(x + 1) = \frac{1}{x + 1}
$$

Let $$ y = x + 1 $$. Then:
$$
f(y) = \frac{1}{y}
$$

Therefore, the function $$ f(x) $$ is:
$$
f(x) = \frac{1}{x}
$$

**Answer:**
$$ f(x) = \dfrac{1}{\,x\,} $$
$$ f(x) = \dfrac{1}{x} $$

The function can be expressed in the form , where , and
is defined as:

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