\( 1 \& \) Solve the equation by the method of your choice \[ x^{2}+4 x=10 \] The solution set is \( \} \) (Simplify your answer Type an exact answer, using radicals and \( i \) as needed Use integers or fractions for any numbers in the expression Use a comma to separate answers as needed)

To solve the equation \( x^{2} + 4x = 10 \), we first rearrange it into standard form: \[ x^{2} + 4x - 10 = 0. \] Next, we can use the quadratic formula \( x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} \). Here, \( a = 1 \), \( b = 4 \), and \( c = -10 \). Calculating the discriminant: \[ b^{2} - 4ac = 4^{2} - 4(1)(-10) = 16 + 40 = 56. \] Thus, our solutions are: \[ x = \frac{-4 \pm \sqrt{56}}{2(1)} = \frac{-4 \pm 2\sqrt{14}}{2} = -2 \pm \sqrt{14}. \] The solution set is: \[ \{-2 + \sqrt{14}, -2 - \sqrt{14}\}. \]