Find the roots and the vertex of the quadratic on a calculator. Round all values to 3 decimal places (if necessary). \[ y=x^{2}+10 x-11 \] Answer Altemp, cour ers Roots: \( \square \) and \( \square \) Anets (tu)

To find the roots of the quadratic equation \( y=x^2+10x-11 \), you can use the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Here, \( a = 1 \), \( b = 10 \), and \( c = -11 \). Plugging in these values gives the roots as approximately \( x \approx -11.414 \) and \( x \approx 1.414 \). The vertex of a quadratic in the form \( y = ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \). For this equation, the vertex \( x \) coordinate is approximately \( -5 \). To find the \( y \) coordinate, substitute \( x = -5 \) into the equation, giving you \( y = -36 \). Hence, the vertex is at \( (-5, -36) \). Roots: \( -11.414 \) and \( 1.414 \) Vertex: \( (-5, -36) \)