7. Airline fares for a flight from Dallas to Austin are \( \$ 30 \) for first class and \( \$ 25 \) for tourist class. If a flight had 52 passengers who paid \( \$ 1360 \), how many first class and tourist class passengers were there?
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To find out how many first class and tourist class passengers were on the flight, we can set up a system of equations. Let \( x \) be the number of first class passengers and \( y \) be the number of tourist class passengers. We have two equations based on the problem: 1. \( x + y = 52 \) (total passengers) 2. \( 30x + 25y = 1360 \) (total fare) Now we can solve these equations: From the first equation, we can express \( y \) as: \( y = 52 - x \) Next, substitute \( y \) in the second equation: \( 30x + 25(52 - x) = 1360 \) Expanding this gives: \( 30x + 1300 - 25x = 1360 \) Combining like terms, we have: \( 5x + 1300 = 1360 \) Subtracting 1300 from both sides results in: \( 5x = 60 \) Now, divide by 5: \( x = 12 \) Using the value of \( x \) to find \( y \): \( y = 52 - 12 = 40 \) Thus, there were 12 first class passengers and 40 tourist class passengers on the flight.