Yoko is making a pennant in the shape of a triangle for her senior class photo. She wants the base length of this triangle to be 4 inches. The area of the pennant must be more than 16 square inches. (The pennant has to be seen in the photo.) Write an inequality that describes the possible heights (in inches) of the triangle. Use \( h \) for the height of the triangular pennant.

To find the inequality for the height of Yoko's triangular pennant, we can use the formula for the area of a triangle, which is given by: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \] In this case, the base is 4 inches, and Yoko wants the area to be more than 16 square inches. Plugging this into the formula gives us: \[ \frac{1}{2} \times 4 \times h > 16 \] Simplifying this inequality: \[ 2h > 16 \] Now, dividing both sides by 2 results in: \[ h > 8 \] So, the inequality that describes the possible heights of the triangular pennant is \( h > 8 \) inches. Now Yoko knows she needs a height that exceeds 8 inches for her pennant to be picture-perfect!