Solve the equation \[ \frac{1}{7}(6 t-4)=\frac{1}{14}(t+4) \]

To solve the equation \[ \frac{1}{7}(6t-4) = \frac{1}{14}(t+4), \] we start by eliminating the fractions. We can do this by finding a common denominator. The least common multiple of 7 and 14 is 14. Thus, we will multiply both sides of the equation by 14: \[ 14 \cdot \frac{1}{7}(6t-4) = 14 \cdot \frac{1}{14}(t+4). \] This simplifies to: \[ 2(6t-4) = t+4. \] Now, distribute the 2 on the left side: \[ 12t - 8 = t + 4. \] Next, we combine like terms. Subtract \(t\) from both sides: \[ 12t - t - 8 = 4. \] This simplifies to: \[ 11t - 8 = 4. \] Now, we add 8 to both sides: \[ 11t = 4 + 8, \] which gives us: \[ 11t = 12. \] Finally, divide both sides by 11 to isolate \(t\): \[ t = \frac{12}{11}. \] Thus, the solution to the equation is \[ \boxed{\frac{12}{11}}. \]