Use logarithms to solve. \[ e^{2 x}-e^{x}-132=0 \] Enter the exact answer (i.e. keep your answer in exponential or logarithmic form, you do not need to calculate its numeric value). Enclose arguments of functions in parentheses and include a multiplication sign between terms. For example, \( c^{*} \ln (h) \). Hints: - Remember by the rule of exponents, that \( e^{2 x}=\left(e^{x}\right)^{2} \) so that you can try to factor this as ( \( e^{x}+ \) something \( )\left(e^{x}+\right. \) something else \( ) \) where the "something" and "something else" can be positive or negative numbers. - Alternately, you could let \( y=e^{x} \) and this equation would be \( y^{2}-y-132=0 \) and you can solve first for \( y \) and then for \( x \). \[ x=\square \square^{\circ} \]