Responder
The function \( M(t) = 975 \cdot 0.92^t \) models the amount of medication in a patient's body over time, decreasing by 8% each unit of time. It starts at 975 mg and approaches zero as time increases. The half-life of the medication is approximately 8.3 time units.
Solución
It appears you're presenting a function that models the amount of medication in a patient's body over time. Let's clarify and analyze the function you've provided:
\[
M(t) = 975 \cdot 0.92^t
\]
**Assumptions:**
1. **Initial Amount (\( M(0) \))**: At time \( t = 0 \), the amount of medication in the patient's body is \( 975 \) milligrams (mg).
\[
M(0) = 975 \cdot 0.92^0 = 975 \cdot 1 = 975 \, \text{mg}
\]
2. **Decay Factor (\( 0.92 \))**: The base of the exponent, \( 0.92 \), represents the retention rate of the medication per unit time. This means that **each unit of time**, \( 8\% \) of the medication is metabolized or eliminated from the body, retaining \( 92\% \) of the previous amount.
3. **Time Variable (\( t \))**: The variable \( t \) typically represents time. The exact unit (e.g., hours, days) should be specified based on the context of the problem.
**Interpreting the Function:**
- **Exponential Decay Model**: The function \( M(t) = 975 \cdot 0.92^t \) is an example of an exponential decay model. It describes a situation where the quantity decreases by a constant percentage over equal intervals of time.
- **General Behavior**:
- As \( t \) increases, \( M(t) \) decreases.
- The medication amount never becomes negative but approaches zero asymptotically.
- **Half-Life Calculation**: If you're interested in finding out how long it takes for the medication amount to reduce to half its initial value, you can calculate the **half-life** (\( t_{1/2} \)) using the formula:
\[
M(t_{1/2}) = \frac{M(0)}{2} \Rightarrow 975 \cdot 0.92^{t_{1/2}} = \frac{975}{2}
\]
\[
0.92^{t_{1/2}} = 0.5
\]
Taking the natural logarithm of both sides:
\[
\ln(0.92^{t_{1/2}}) = \ln(0.5)
\]
\[
t_{1/2} \cdot \ln(0.92) = \ln(0.5)
\]
\[
t_{1/2} = \frac{\ln(0.5)}{\ln(0.92)} \approx \frac{-0.6931}{-0.0834} \approx 8.3 \, \text{units of time}
\]
So, the half-life of the medication is approximately \( 8.3 \) time units (e.g., hours or days, depending on the context).
**Practical Implications:**
- **Dosing Schedule**: Understanding the decay rate helps healthcare providers determine how frequently a medication should be administered to maintain its therapeutic level without causing toxicity.
- **Patient Safety**: Knowing how long a medication stays in the body ensures that dosages are safe and effective, preventing potential side effects from accumulation or ineffectiveness due to rapid clearance.
**Graphical Representation:**
Plotting \( M(t) = 975 \cdot 0.92^t \) will yield a curve that starts at \( 975 \) mg when \( t = 0 \) and decreases exponentially towards zero as \( t \) increases. Here's a rough sketch of the behavior:
```
M(t)
|
|\
| \
| \
| \
| \
| \
| \
|_______\________ t
```
**Key Points on the Graph:**
- At \( t = 0 \), \( M(t) = 975 \) mg.
- As \( t \) approaches infinity, \( M(t) \) approaches \( 0 \) mg.
- The curve is always decreasing but never touches the \( t \)-axis.
**Conclusion:**
The function \( M(t) = 975 \cdot 0.92^t \) effectively models the exponential decay of a medication in a patient's body, allowing for the analysis of dosage schedules, half-life calculations, and ensuring patient safety through appropriate medication management.
If you have a specific question or a particular aspect of this model you'd like to explore further, please provide more details!
Revisado y aprobado por el equipo de tutoría de UpStudy
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