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3. The function \( M(t)=975 \cdot 0.92^{\prime} \) represents the number of milligrams of a medication in a patient's body as a function of time.

Ask by Bond Chang. in the United States
Jan 24,2025

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The function \( M(t) = 975 \cdot 0.92^t \) models the amount of medication in a patient's body over time, decreasing by 8% each unit of time. It starts at 975 mg and approaches zero as time increases. The half-life of the medication is approximately 8.3 time units.

Solución

It appears you're presenting a function that models the amount of medication in a patient's body over time. Let's clarify and analyze the function you've provided: \[ M(t) = 975 \cdot 0.92^t \] **Assumptions:** 1. **Initial Amount (\( M(0) \))**: At time \( t = 0 \), the amount of medication in the patient's body is \( 975 \) milligrams (mg). \[ M(0) = 975 \cdot 0.92^0 = 975 \cdot 1 = 975 \, \text{mg} \] 2. **Decay Factor (\( 0.92 \))**: The base of the exponent, \( 0.92 \), represents the retention rate of the medication per unit time. This means that **each unit of time**, \( 8\% \) of the medication is metabolized or eliminated from the body, retaining \( 92\% \) of the previous amount. 3. **Time Variable (\( t \))**: The variable \( t \) typically represents time. The exact unit (e.g., hours, days) should be specified based on the context of the problem. **Interpreting the Function:** - **Exponential Decay Model**: The function \( M(t) = 975 \cdot 0.92^t \) is an example of an exponential decay model. It describes a situation where the quantity decreases by a constant percentage over equal intervals of time. - **General Behavior**: - As \( t \) increases, \( M(t) \) decreases. - The medication amount never becomes negative but approaches zero asymptotically. - **Half-Life Calculation**: If you're interested in finding out how long it takes for the medication amount to reduce to half its initial value, you can calculate the **half-life** (\( t_{1/2} \)) using the formula: \[ M(t_{1/2}) = \frac{M(0)}{2} \Rightarrow 975 \cdot 0.92^{t_{1/2}} = \frac{975}{2} \] \[ 0.92^{t_{1/2}} = 0.5 \] Taking the natural logarithm of both sides: \[ \ln(0.92^{t_{1/2}}) = \ln(0.5) \] \[ t_{1/2} \cdot \ln(0.92) = \ln(0.5) \] \[ t_{1/2} = \frac{\ln(0.5)}{\ln(0.92)} \approx \frac{-0.6931}{-0.0834} \approx 8.3 \, \text{units of time} \] So, the half-life of the medication is approximately \( 8.3 \) time units (e.g., hours or days, depending on the context). **Practical Implications:** - **Dosing Schedule**: Understanding the decay rate helps healthcare providers determine how frequently a medication should be administered to maintain its therapeutic level without causing toxicity. - **Patient Safety**: Knowing how long a medication stays in the body ensures that dosages are safe and effective, preventing potential side effects from accumulation or ineffectiveness due to rapid clearance. **Graphical Representation:** Plotting \( M(t) = 975 \cdot 0.92^t \) will yield a curve that starts at \( 975 \) mg when \( t = 0 \) and decreases exponentially towards zero as \( t \) increases. Here's a rough sketch of the behavior: ``` M(t) | |\ | \ | \ | \ | \ | \ | \ |_______\________ t ``` **Key Points on the Graph:** - At \( t = 0 \), \( M(t) = 975 \) mg. - As \( t \) approaches infinity, \( M(t) \) approaches \( 0 \) mg. - The curve is always decreasing but never touches the \( t \)-axis. **Conclusion:** The function \( M(t) = 975 \cdot 0.92^t \) effectively models the exponential decay of a medication in a patient's body, allowing for the analysis of dosage schedules, half-life calculations, and ensuring patient safety through appropriate medication management. If you have a specific question or a particular aspect of this model you'd like to explore further, please provide more details!

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The Deep Dive

The formula you’ve presented shows a classic example of exponential decay, where the medication in the body decreases over time. The factor \(0.92\) suggests that the body retains 92% of the medication after each unit of time, which means around 8% is eliminated with each passing interval. This kind of model is often used in pharmacokinetics to understand how the body absorbs and eliminates medications, making it crucial for determining dosage intervals. If you want to ensure optimal medication levels without falling into the common pitfall of overdosing or underdosing, always remember to factor in the patient’s unique metabolism rate, as it can vary significantly among individuals. A common mistake is assuming that all patients will process medications at the same rate, leading to either a lack of therapeutic effect or potential toxicity. Keeping track of how the specific characteristics of the patient's health might affect their medication response can make all the difference!

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