5) \( \begin{array}{l}y=-2 \\ 4 x-3 y=18\end{array} \)

To solve the system of equations, we can start with the first equation \( y = -2 \). Now, we’ll substitute \( y \) into the second equation \( 4x - 3y = 18 \). Plugging \( y = -2 \) into this equation gives us: \[ 4x - 3(-2) = 18 \] \[ 4x + 6 = 18 \] Now, subtract 6 from both sides: \[ 4x = 12 \] Dividing both sides by 4 yields: \[ x = 3 \] So, the solution to the system is \( (3, -2) \). To validate, you can plug \( x = 3 \) and \( y = -2 \) back into both original equations, and you’ll find they hold true. Solving systems like this is quick and simple with substitution when one equation is solved for a variable already!