Factor. \[ d^{2}-2 d-3 \]

To factor the expression \( d^{2}-2d-3 \), we will find two numbers that multiply to \(-3\) (the constant term) and add to \(-2\) (the coefficient of \(d\)). Those numbers are \(-3\) and \(1\). Thus, we can write the expression as: \[ (d - 3)(d + 1) \] And there you have it! The expression \( d^{2}-2d-3 \) factors nicely into \( (d - 3)(d + 1) \). Now, let’s check the roots quickly! Setting \(d - 3 = 0\) gives \(d = 3\), and \(d + 1 = 0\) gives \(d = -1\). Those values are the solutions to the equation \(d^{2}-2d-3=0\). Happy factoring!